Search a number
-
+
411334244011241 is a prime number
BaseRepresentation
bin101110110000110110011011…
…1011111111000110011101001
31222221102011120200222211111222
41131201230313133320303221
5412403300012431324431
64014500202031431425
7152432630010263645
oct13541546737706351
91887364520884458
10411334244011241
1110a077967312341
123a1733ba085575
13148698641b0a45
14738097dc7bc25
153284b3349557b
hex1761b377f8ce9

411334244011241 has 2 divisors, whose sum is σ = 411334244011242. Its totient is φ = 411334244011240.

The previous prime is 411334244011199. The next prime is 411334244011349. The reversal of 411334244011241 is 142110442433114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 251964954547216 + 159369289464025 = 15873404^2 + 12624155^2 .

It is a cyclic number.

It is not a de Polignac number, because 411334244011241 - 222 = 411334239816937 is a prime.

It is not a weakly prime, because it can be changed into another prime (411334244011841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205667122005620 + 205667122005621.

It is an arithmetic number, because the mean of its divisors is an integer number (205667122005621).

Almost surely, 2411334244011241 is an apocalyptic number.

It is an amenable number.

411334244011241 is a deficient number, since it is larger than the sum of its proper divisors (1).

411334244011241 is an equidigital number, since it uses as much as digits as its factorization.

411334244011241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36864, while the sum is 35.

Adding to 411334244011241 its reverse (142110442433114), we get a palindrome (553444686444355).

The spelling of 411334244011241 in words is "four hundred eleven trillion, three hundred thirty-four billion, two hundred forty-four million, eleven thousand, two hundred forty-one".