Base | Representation |
---|---|
bin | 10010101101001010001000… |
… | …11101101110000000010011 |
3 | 12101122101011200220002210211 |
4 | 21112211010131232000103 |
5 | 20342420013402410331 |
6 | 223252415532504551 |
7 | 11443560054512545 |
oct | 1126450435560023 |
9 | 171571150802724 |
10 | 41134050435091 |
11 | 12119942120a09 |
12 | 474407a31b157 |
13 | 19c4c02937983 |
14 | a22c81d0d695 |
15 | 4b4ecebd08b1 |
hex | 25694476e013 |
41134050435091 has 2 divisors, whose sum is σ = 41134050435092. Its totient is φ = 41134050435090.
The previous prime is 41134050435029. The next prime is 41134050435167. The reversal of 41134050435091 is 19053405043114.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41134050435091 - 221 = 41134048337939 is a prime.
It is a super-2 number, since 2×411340504350912 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (41134050435011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20567025217545 + 20567025217546.
It is an arithmetic number, because the mean of its divisors is an integer number (20567025217546).
Almost surely, 241134050435091 is an apocalyptic number.
41134050435091 is a deficient number, since it is larger than the sum of its proper divisors (1).
41134050435091 is an equidigital number, since it uses as much as digits as its factorization.
41134050435091 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 40.
The spelling of 41134050435091 in words is "forty-one trillion, one hundred thirty-four billion, fifty million, four hundred thirty-five thousand, ninety-one".
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