Base | Representation |
---|---|
bin | 10010101101001010110011… |
… | …11101101010100110110010 |
3 | 12101122102002211121101000012 |
4 | 21112211121331222212302 |
5 | 20342421233222200224 |
6 | 223252515415454522 |
7 | 11443602024416204 |
oct | 1126453175524662 |
9 | 171572084541005 |
10 | 41134411131314 |
11 | 1211a007791366 |
12 | 474415b087442 |
13 | 19c4c5c5975a7 |
14 | a22cb7ba2774 |
15 | 4b50016cd80e |
hex | 256959f6a9b2 |
41134411131314 has 4 divisors (see below), whose sum is σ = 61701616696974. Its totient is φ = 20567205565656.
The previous prime is 41134411131259. The next prime is 41134411131353. The reversal of 41134411131314 is 41313111443114.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 36917569416289 + 4216841715025 = 6075983^2 + 2053495^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10283602782827 + ... + 10283602782830.
Almost surely, 241134411131314 is an apocalyptic number.
41134411131314 is a deficient number, since it is larger than the sum of its proper divisors (20567205565660).
41134411131314 is a wasteful number, since it uses less digits than its factorization.
41134411131314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20567205565659.
The product of its digits is 6912, while the sum is 32.
Adding to 41134411131314 its reverse (41313111443114), we get a palindrome (82447522574428).
The spelling of 41134411131314 in words is "forty-one trillion, one hundred thirty-four billion, four hundred eleven million, one hundred thirty-one thousand, three hundred fourteen".
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