Base | Representation |
---|---|
bin | 10010101101001010110101… |
… | …00100001000000000111001 |
3 | 12101122102010112120120210220 |
4 | 21112211122210020000321 |
5 | 20342421243312310431 |
6 | 223252520415530253 |
7 | 11443602206206446 |
oct | 1126453244100071 |
9 | 171572115516726 |
10 | 41134421213241 |
11 | 1211a012448034 |
12 | 4744162529989 |
13 | 19c4c616b7525 |
14 | a22cb92689cd |
15 | 4b5002520b96 |
hex | 25695a908039 |
41134421213241 has 32 divisors (see below), whose sum is σ = 61149951826560. Its totient is φ = 24442860589056.
The previous prime is 41134421213219. The next prime is 41134421213351. The reversal of 41134421213241 is 14231212443114.
It is not a de Polignac number, because 41134421213241 - 217 = 41134421082169 is a prime.
It is a super-3 number, since 3×411344212132413 (a number of 42 digits) contains 333 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (41134421213741) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4660756 + ... + 10197621.
It is an arithmetic number, because the mean of its divisors is an integer number (1910935994580).
Almost surely, 241134421213241 is an apocalyptic number.
It is an amenable number.
41134421213241 is a deficient number, since it is larger than the sum of its proper divisors (20015530613319).
41134421213241 is a wasteful number, since it uses less digits than its factorization.
41134421213241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14861273.
The product of its digits is 18432, while the sum is 33.
Adding to 41134421213241 its reverse (14231212443114), we get a palindrome (55365633656355).
The spelling of 41134421213241 in words is "forty-one trillion, one hundred thirty-four billion, four hundred twenty-one million, two hundred thirteen thousand, two hundred forty-one".
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