Base | Representation |
---|---|
bin | 10010101101001011111010… |
… | …01000011010110111101001 |
3 | 12101122110121221211120121021 |
4 | 21112211331020122313221 |
5 | 20342423440243344001 |
6 | 223253054134012441 |
7 | 11443622450466100 |
oct | 1126457510326751 |
9 | 171573557746537 |
10 | 41135001153001 |
11 | 1211a28a844398 |
12 | 47442a47a7121 |
13 | 19c50248ab452 |
14 | a22d322ad037 |
15 | 4b50383c9ba1 |
hex | 25697d21ade9 |
41135001153001 has 12 divisors (see below), whose sum is σ = 47856415888848. Its totient is φ = 35254522599912.
The previous prime is 41135001152969. The next prime is 41135001153049. The reversal of 41135001153001 is 10035110053114.
It is not a de Polignac number, because 41135001153001 - 25 = 41135001152969 is a prime.
It is a super-2 number, since 2×411350011530012 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (41135001153401) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 47781111 + ... + 48634396.
It is an arithmetic number, because the mean of its divisors is an integer number (3988034657404).
Almost surely, 241135001153001 is an apocalyptic number.
It is an amenable number.
41135001153001 is a deficient number, since it is larger than the sum of its proper divisors (6721414735847).
41135001153001 is an equidigital number, since it uses as much as digits as its factorization.
41135001153001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 96424228 (or 96424221 counting only the distinct ones).
The product of its (nonzero) digits is 900, while the sum is 25.
The spelling of 41135001153001 in words is "forty-one trillion, one hundred thirty-five billion, one million, one hundred fifty-three thousand, one".
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