Search a number
-
+
41141035321 = 79520772599
BaseRepresentation
bin100110010100001100…
…100110000100111001
310221012012010010200221
4212110030212010321
51133224101112241
630522215100041
72654341013251
oct462414460471
9127165103627
1041141035321
11164a2050841
127b82071621
133b585a00a9
141dc3d4c961
15110bc765d1
hex994326139

41141035321 has 4 divisors (see below), whose sum is σ = 41661808000. Its totient is φ = 40620262644.

The previous prime is 41141035277. The next prime is 41141035343. The reversal of 41141035321 is 12353014114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 41141035321 - 213 = 41141027129 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (41141035391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 260386221 + ... + 260386378.

It is an arithmetic number, because the mean of its divisors is an integer number (10415452000).

Almost surely, 241141035321 is an apocalyptic number.

It is an amenable number.

41141035321 is a deficient number, since it is larger than the sum of its proper divisors (520772679).

41141035321 is an equidigital number, since it uses as much as digits as its factorization.

41141035321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 520772678.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 41141035321 its reverse (12353014114), we get a palindrome (53494049435).

The spelling of 41141035321 in words is "forty-one billion, one hundred forty-one million, thirty-five thousand, three hundred twenty-one".

Divisors: 1 79 520772599 41141035321