Base | Representation |
---|---|
bin | 101110110001011010010001… |
… | …1111011001011110110100001 |
3 | 1222221200112021122100222111102 |
4 | 1131202310203323023312201 |
5 | 412411030142102043040 |
6 | 4014555412502124145 |
7 | 152441323453214030 |
oct | 13542644373136641 |
9 | 1887615248328442 |
10 | 411411225034145 |
11 | 10a0a7580077226 |
12 | 3a186302a20655 |
13 | 14873bb1a1867b |
14 | 73845a3ab0717 |
15 | 3286b3b8c2515 |
hex | 1762d23ecbda1 |
411411225034145 has 32 divisors (see below), whose sum is σ = 568366766438400. Its totient is φ = 280037922909696.
The previous prime is 411411225034133. The next prime is 411411225034151. The reversal of 411411225034145 is 541430522114114.
It is not a de Polignac number, because 411411225034145 - 24 = 411411225034129 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 411411225034099 and 411411225034108.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 98451551 + ... + 102545259.
It is an arithmetic number, because the mean of its divisors is an integer number (17761461451200).
Almost surely, 2411411225034145 is an apocalyptic number.
It is an amenable number.
411411225034145 is a deficient number, since it is larger than the sum of its proper divisors (156955541404255).
411411225034145 is a wasteful number, since it uses less digits than its factorization.
411411225034145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4114817.
The product of its (nonzero) digits is 76800, while the sum is 38.
Adding to 411411225034145 its reverse (541430522114114), we get a palindrome (952841747148259).
The spelling of 411411225034145 in words is "four hundred eleven trillion, four hundred eleven billion, two hundred twenty-five million, thirty-four thousand, one hundred forty-five".
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