Base | Representation |
---|---|
bin | 100110010100001101… |
… | …000000001100111011 |
3 | 10221012012022120111021 |
4 | 212110031000030323 |
5 | 1133224113023311 |
6 | 30522221243311 |
7 | 2654341640242 |
oct | 462415001473 |
9 | 127165276437 |
10 | 41141142331 |
11 | 164a2114183 |
12 | 7b82103537 |
13 | 3b58609a03 |
14 | 1dc3d79959 |
15 | 110bc98171 |
hex | 99434033b |
41141142331 has 2 divisors, whose sum is σ = 41141142332. Its totient is φ = 41141142330.
The previous prime is 41141142307. The next prime is 41141142347. The reversal of 41141142331 is 13324114114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41141142331 - 211 = 41141140283 is a prime.
It is a super-2 number, since 2×411411423312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 41141142296 and 41141142305.
It is not a weakly prime, because it can be changed into another prime (41141142431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20570571165 + 20570571166.
It is an arithmetic number, because the mean of its divisors is an integer number (20570571166).
Almost surely, 241141142331 is an apocalyptic number.
41141142331 is a deficient number, since it is larger than the sum of its proper divisors (1).
41141142331 is an equidigital number, since it uses as much as digits as its factorization.
41141142331 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1152, while the sum is 25.
Adding to 41141142331 its reverse (13324114114), we get a palindrome (54465256445).
The spelling of 41141142331 in words is "forty-one billion, one hundred forty-one million, one hundred forty-two thousand, three hundred thirty-one".
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