Base | Representation |
---|---|
bin | 10010101101011001011000… |
… | …01111111101100111101011 |
3 | 12101200011022000220212220221 |
4 | 21112230230033331213223 |
5 | 20343033243413013233 |
6 | 223300251553230511 |
7 | 11444266625556424 |
oct | 1126545417754753 |
9 | 171604260825827 |
10 | 41142234110443 |
11 | 12122361641374 |
12 | 4745782b62437 |
13 | 19c590823a81b |
14 | a2341ab4a64b |
15 | 4b530d3ad42d |
hex | 256b2c3fd9eb |
41142234110443 has 2 divisors, whose sum is σ = 41142234110444. Its totient is φ = 41142234110442.
The previous prime is 41142234110423. The next prime is 41142234110449. The reversal of 41142234110443 is 34401143224114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41142234110443 - 221 = 41142232013291 is a prime.
It is a super-3 number, since 3×411422341104433 (a number of 42 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 41142234110399 and 41142234110408.
It is not a weakly prime, because it can be changed into another prime (41142234110449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20571117055221 + 20571117055222.
It is an arithmetic number, because the mean of its divisors is an integer number (20571117055222).
Almost surely, 241142234110443 is an apocalyptic number.
41142234110443 is a deficient number, since it is larger than the sum of its proper divisors (1).
41142234110443 is an equidigital number, since it uses as much as digits as its factorization.
41142234110443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36864, while the sum is 34.
Adding to 41142234110443 its reverse (34401143224114), we get a palindrome (75543377334557).
The spelling of 41142234110443 in words is "forty-one trillion, one hundred forty-two billion, two hundred thirty-four million, one hundred ten thousand, four hundred forty-three".
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