4114303421233 has 4 divisors (see below), whose sum is σ = 4121433930340. Its totient is φ = 4107172912128.

The previous prime is 4114303421197. The next prime is 4114303421269. The reversal of 4114303421233 is 3321243034114.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (4114303421197) and next prime (4114303421269).

It can be written as a sum of positive squares in 2 ways, for example, as 3616873668864 + 497429752369 = 1901808^2 + 705287^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4114303421233 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4114303421195 and 4114303421204.

It is not an unprimeable number, because it can be changed into a prime (4114307421233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3565253688 + ... + 3565254841.

It is an arithmetic number, because the mean of its divisors is an integer number (1030358482585).

Almost surely, 2^{4114303421233} is an apocalyptic number.

It is an amenable number.

4114303421233 is a deficient number, since it is larger than the sum of its proper divisors (7130509107).

4114303421233 is an equidigital number, since it uses as much as digits as its factorization.

4114303421233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7130509106.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 4114303421233 its reverse (3321243034114), we get a palindrome (7435546455347).

The spelling of 4114303421233 in words is "four trillion, one hundred fourteen billion, three hundred three million, four hundred twenty-one thousand, two hundred thirty-three".