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4114311011553 = 347910067284407
BaseRepresentation
bin111011110111110000000…
…010111101110011100001
3112120022202102000202101210
4323313300002331303201
51014402102104332203
612430031031420333
7603151314401301
oct73676002756341
915508672022353
104114311011553
111346962340546
1256546a5246a9
1323ac9349bc42
141031c2cb5601
15720517ae803
hex3bdf00bdce1

4114311011553 has 16 divisors (see below), whose sum is σ = 5497765908480. Its totient is φ = 2736866240976.

The previous prime is 4114311011537. The next prime is 4114311011579. The reversal of 4114311011553 is 3551101134114.

It is not a de Polignac number, because 4114311011553 - 24 = 4114311011537 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 4114311011553.

It is not an unprimeable number, because it can be changed into a prime (4114311011453) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14324076 + ... + 14608482.

It is an arithmetic number, because the mean of its divisors is an integer number (343610369280).

Almost surely, 24114311011553 is an apocalyptic number.

It is an amenable number.

4114311011553 is a deficient number, since it is larger than the sum of its proper divisors (1383454896927).

4114311011553 is a wasteful number, since it uses less digits than its factorization.

4114311011553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 294956.

The product of its (nonzero) digits is 3600, while the sum is 30.

Adding to 4114311011553 its reverse (3551101134114), we get a palindrome (7665412145667).

The spelling of 4114311011553 in words is "four trillion, one hundred fourteen billion, three hundred eleven million, eleven thousand, five hundred fifty-three".

Divisors: 1 3 479 1437 10067 30201 284407 853221 4822093 14466279 136230953 408692859 2863125269 8589375807 1371437003851 4114311011553