411431121341401 has 4 divisors (see below), whose sum is σ = 470206995818752. Its totient is φ = 352655246864052.

The previous prime is 411431121341393. The next prime is 411431121341441. The reversal of 411431121341401 is 104143121134114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 411431121341401 - 2³ = 411431121341393 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (411431121341441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29387937238665 + ... + 29387937238678.

It is an arithmetic number, because the mean of its divisors is an integer number (117551748954688).

Almost surely, 2^{411431121341401} is an apocalyptic number.

It is an amenable number.

411431121341401 is a deficient number, since it is larger than the sum of its proper divisors (58775874477351).

411431121341401 is an equidigital number, since it uses as much as digits as its factorization.

411431121341401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58775874477350.

The product of its (nonzero) digits is 4608, while the sum is 31.

Adding to 411431121341401 its reverse (104143121134114), we get a palindrome (515574242475515).

The spelling of 411431121341401 in words is "four hundred eleven trillion, four hundred thirty-one billion, one hundred twenty-one million, three hundred forty-one thousand, four hundred one".