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4114322200003 is a prime number
BaseRepresentation
bin111011110111110000101…
…101101001010111000011
3112120022210012002012001211
4323313300231221113003
51014402112440400003
612430032111310551
7603151511450551
oct73676055512703
915508705065054
104114322200003
1113469686925a4
1256547221b457
1323ac958b8722
141031c4588bd1
157205276e96d
hex3bdf0b695c3

4114322200003 has 2 divisors, whose sum is σ = 4114322200004. Its totient is φ = 4114322200002.

The previous prime is 4114322199973. The next prime is 4114322200007. The reversal of 4114322200003 is 3000022234114.

4114322200003 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4114322200003 - 25 = 4114322199971 is a prime.

It is not a weakly prime, because it can be changed into another prime (4114322200007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2057161100001 + 2057161100002.

It is an arithmetic number, because the mean of its divisors is an integer number (2057161100002).

Almost surely, 24114322200003 is an apocalyptic number.

4114322200003 is a deficient number, since it is larger than the sum of its proper divisors (1).

4114322200003 is an equidigital number, since it uses as much as digits as its factorization.

4114322200003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 4114322200003 its reverse (3000022234114), we get a palindrome (7114344434117).

The spelling of 4114322200003 in words is "four trillion, one hundred fourteen billion, three hundred twenty-two million, two hundred thousand, three".