Base | Representation |
---|---|
bin | 111011110111110000101… |
… | …101101001010111000011 |
3 | 112120022210012002012001211 |
4 | 323313300231221113003 |
5 | 1014402112440400003 |
6 | 12430032111310551 |
7 | 603151511450551 |
oct | 73676055512703 |
9 | 15508705065054 |
10 | 4114322200003 |
11 | 13469686925a4 |
12 | 56547221b457 |
13 | 23ac958b8722 |
14 | 1031c4588bd1 |
15 | 7205276e96d |
hex | 3bdf0b695c3 |
4114322200003 has 2 divisors, whose sum is σ = 4114322200004. Its totient is φ = 4114322200002.
The previous prime is 4114322199973. The next prime is 4114322200007. The reversal of 4114322200003 is 3000022234114.
4114322200003 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4114322200003 - 25 = 4114322199971 is a prime.
It is not a weakly prime, because it can be changed into another prime (4114322200007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2057161100001 + 2057161100002.
It is an arithmetic number, because the mean of its divisors is an integer number (2057161100002).
Almost surely, 24114322200003 is an apocalyptic number.
4114322200003 is a deficient number, since it is larger than the sum of its proper divisors (1).
4114322200003 is an equidigital number, since it uses as much as digits as its factorization.
4114322200003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 4114322200003 its reverse (3000022234114), we get a palindrome (7114344434117).
The spelling of 4114322200003 in words is "four trillion, one hundred fourteen billion, three hundred twenty-two million, two hundred thousand, three".
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