411434333214441 has 4 divisors (see below), whose sum is σ = 548579110952592. Its totient is φ = 274289555476292.

The previous prime is 411434333214323. The next prime is 411434333214461. The reversal of 411434333214441 is 144412333434114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 411434333214441 - 2¹⁰ = 411434333213417 is a prime.

It is a super-2 number, since 2×411434333214441² (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 411434333214393 and 411434333214402.

It is not an unprimeable number, because it can be changed into a prime (411434333214461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68572388869071 + ... + 68572388869076.

It is an arithmetic number, because the mean of its divisors is an integer number (137144777738148).

Almost surely, 2^{411434333214441} is an apocalyptic number.

It is an amenable number.

411434333214441 is a deficient number, since it is larger than the sum of its proper divisors (137144777738151).

411434333214441 is a wasteful number, since it uses less digits than its factorization.

411434333214441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 137144777738150.

The product of its digits is 663552, while the sum is 42.

Adding to 411434333214441 its reverse (144412333434114), we get a palindrome (555846666648555).

The spelling of 411434333214441 in words is "four hundred eleven trillion, four hundred thirty-four billion, three hundred thirty-three million, two hundred fourteen thousand, four hundred forty-one".