Base | Representation |
---|---|
bin | 10010101101011101010011… |
… | …10010110111101011001011 |
3 | 12101200100201211022011000121 |
4 | 21112232221302313223023 |
5 | 20343102102121210011 |
6 | 223301240554444111 |
7 | 11444403053053534 |
oct | 1126565162675313 |
9 | 171610654264017 |
10 | 41144340413131 |
11 | 1212324259479a |
12 | 4746070433637 |
13 | 19c5b82724387 |
14 | a2357a79768b |
15 | 4b53d326ce71 |
hex | 256ba9cb7acb |
41144340413131 has 2 divisors, whose sum is σ = 41144340413132. Its totient is φ = 41144340413130.
The previous prime is 41144340413051. The next prime is 41144340413149. The reversal of 41144340413131 is 13131404344114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41144340413131 - 29 = 41144340412619 is a prime.
It is a super-2 number, since 2×411443404131312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (41144340113131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20572170206565 + 20572170206566.
It is an arithmetic number, because the mean of its divisors is an integer number (20572170206566).
Almost surely, 241144340413131 is an apocalyptic number.
41144340413131 is a deficient number, since it is larger than the sum of its proper divisors (1).
41144340413131 is an equidigital number, since it uses as much as digits as its factorization.
41144340413131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 34.
Adding to 41144340413131 its reverse (13131404344114), we get a palindrome (54275744757245).
The spelling of 41144340413131 in words is "forty-one trillion, one hundred forty-four billion, three hundred forty million, four hundred thirteen thousand, one hundred thirty-one".
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