Base | Representation |
---|---|
bin | 1011111110011000001… |
… | …00001100010011001001 |
3 | 1110100000100101020212221 |
4 | 11333030010030103021 |
5 | 23220120024403022 |
6 | 513003201534041 |
7 | 41504001264235 |
oct | 5771404142311 |
9 | 1410010336787 |
10 | 411445544137 |
11 | 149547313091 |
12 | 678a8344321 |
13 | 2ca50962474 |
14 | 15cb22d15c5 |
15 | aa81645cc7 |
hex | 5fcc10c4c9 |
411445544137 has 2 divisors, whose sum is σ = 411445544138. Its totient is φ = 411445544136.
The previous prime is 411445544101. The next prime is 411445544143. The reversal of 411445544137 is 731445544114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 296426891401 + 115018652736 = 544451^2 + 339144^2 .
It is a cyclic number.
It is not a de Polignac number, because 411445544137 - 215 = 411445511369 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 411445544093 and 411445544102.
It is not a weakly prime, because it can be changed into another prime (411445544197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205722772068 + 205722772069.
It is an arithmetic number, because the mean of its divisors is an integer number (205722772069).
Almost surely, 2411445544137 is an apocalyptic number.
It is an amenable number.
411445544137 is a deficient number, since it is larger than the sum of its proper divisors (1).
411445544137 is an equidigital number, since it uses as much as digits as its factorization.
411445544137 is an evil number, because the sum of its binary digits is even.
The product of its digits is 537600, while the sum is 43.
The spelling of 411445544137 in words is "four hundred eleven billion, four hundred forty-five million, five hundred forty-four thousand, one hundred thirty-seven".
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