Base | Representation |
---|---|
bin | 10010101101011110110001… |
… | …00010000000111000010011 |
3 | 12101200102202110202002021211 |
4 | 21112233120202000320103 |
5 | 20343110203334223124 |
6 | 223301450445000551 |
7 | 11444431353640651 |
oct | 1126573042007023 |
9 | 171612673662254 |
10 | 41145124523539 |
11 | 12123605162523 |
12 | 474624ab53157 |
13 | 19c5c79002a2a |
14 | a23612987dd1 |
15 | 4b542c006e94 |
hex | 256bd8880e13 |
41145124523539 has 2 divisors, whose sum is σ = 41145124523540. Its totient is φ = 41145124523538.
The previous prime is 41145124523441. The next prime is 41145124523543. The reversal of 41145124523539 is 93532542154114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41145124523539 - 219 = 41145123999251 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 41145124523492 and 41145124523501.
It is not a weakly prime, because it can be changed into another prime (41145124529539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20572562261769 + 20572562261770.
It is an arithmetic number, because the mean of its divisors is an integer number (20572562261770).
Almost surely, 241145124523539 is an apocalyptic number.
41145124523539 is a deficient number, since it is larger than the sum of its proper divisors (1).
41145124523539 is an equidigital number, since it uses as much as digits as its factorization.
41145124523539 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2592000, while the sum is 49.
The spelling of 41145124523539 in words is "forty-one trillion, one hundred forty-five billion, one hundred twenty-four million, five hundred twenty-three thousand, five hundred thirty-nine".
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