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41145849881 is a prime number
BaseRepresentation
bin100110010100011110…
…111101100000011001
310221012112011202000222
4212110132331200121
51133231314144011
630522510205425
72654426645003
oct462436754031
9127175152028
1041145849881
11164a483a014
127b837b3875
133b59597646
141dc4843373
15110c3c7ddb
hex9947bd819

41145849881 has 2 divisors, whose sum is σ = 41145849882. Its totient is φ = 41145849880.

The previous prime is 41145849863. The next prime is 41145849929. The reversal of 41145849881 is 18894854114.

41145849881 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 29501497600 + 11644352281 = 171760^2 + 107909^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41145849881 is a prime.

It is a super-2 number, since 2×411458498812 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (41145849821) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20572924940 + 20572924941.

It is an arithmetic number, because the mean of its divisors is an integer number (20572924941).

Almost surely, 241145849881 is an apocalyptic number.

It is an amenable number.

41145849881 is a deficient number, since it is larger than the sum of its proper divisors (1).

41145849881 is an equidigital number, since it uses as much as digits as its factorization.

41145849881 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1474560, while the sum is 53.

The spelling of 41145849881 in words is "forty-one billion, one hundred forty-five million, eight hundred forty-nine thousand, eight hundred eighty-one".