Base | Representation |
---|---|
bin | 100110010100110110… |
… | …000101110001111001 |
3 | 10221012221120210011221 |
4 | 212110312011301321 |
5 | 1133234342204311 |
6 | 30523244152041 |
7 | 2654532326656 |
oct | 462466056171 |
9 | 127187523157 |
10 | 41151913081 |
11 | 164a8200424 |
12 | 7b85838621 |
13 | 3b5a90b336 |
14 | 1dc5580c2d |
15 | 110cbc4671 |
hex | 994d85c79 |
41151913081 has 2 divisors, whose sum is σ = 41151913082. Its totient is φ = 41151913080.
The previous prime is 41151913063. The next prime is 41151913091. The reversal of 41151913081 is 18031915114.
41151913081 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 34860250681 + 6291662400 = 186709^2 + 79320^2 .
It is a cyclic number.
It is not a de Polignac number, because 41151913081 - 225 = 41118358649 is a prime.
It is a super-3 number, since 3×411519130813 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (41151913091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20575956540 + 20575956541.
It is an arithmetic number, because the mean of its divisors is an integer number (20575956541).
Almost surely, 241151913081 is an apocalyptic number.
It is an amenable number.
41151913081 is a deficient number, since it is larger than the sum of its proper divisors (1).
41151913081 is an equidigital number, since it uses as much as digits as its factorization.
41151913081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 34.
The spelling of 41151913081 in words is "forty-one billion, one hundred fifty-one million, nine hundred thirteen thousand, eighty-one".
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