Search a number
-
+
41162432413153 is a prime number
BaseRepresentation
bin10010101101111111000000…
…01010010111110111100001
312101202002102200120222100111
421112333200022113313201
520343401130144210103
6223313432125051321
711445613306401352
oct1126774012276741
9171662380528314
1041162432413153
111212a986aa4127
12474967b3b6b41
1319c77a6a2702c
14a243b54d1d29
154b5ae174a86d
hex256fe0297de1

41162432413153 has 2 divisors, whose sum is σ = 41162432413154. Its totient is φ = 41162432413152.

The previous prime is 41162432413097. The next prime is 41162432413177. The reversal of 41162432413153 is 35131423426114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40842989285904 + 319443127249 = 6390852^2 + 565193^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41162432413153 is a prime.

It is not a weakly prime, because it can be changed into another prime (41162432414153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20581216206576 + 20581216206577.

It is an arithmetic number, because the mean of its divisors is an integer number (20581216206577).

Almost surely, 241162432413153 is an apocalyptic number.

It is an amenable number.

41162432413153 is a deficient number, since it is larger than the sum of its proper divisors (1).

41162432413153 is an equidigital number, since it uses as much as digits as its factorization.

41162432413153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 207360, while the sum is 40.

Adding to 41162432413153 its reverse (35131423426114), we get a palindrome (76293855839267).

The spelling of 41162432413153 in words is "forty-one trillion, one hundred sixty-two billion, four hundred thirty-two million, four hundred thirteen thousand, one hundred fifty-three".