Base | Representation |
---|---|
bin | 1011111111010000101… |
… | …10010000000101111001 |
3 | 1110101020102020011021101 |
4 | 11333220112100011321 |
5 | 23222103012242223 |
6 | 513122232011401 |
7 | 41521522400065 |
oct | 5775026200571 |
9 | 1411212204241 |
10 | 411920040313 |
11 | 149770140091 |
12 | 679bb230b61 |
13 | 2cac8057c32 |
14 | 15d19328aa5 |
15 | aaad1224ad |
hex | 5fe8590179 |
411920040313 has 2 divisors, whose sum is σ = 411920040314. Its totient is φ = 411920040312.
The previous prime is 411920040281. The next prime is 411920040391. The reversal of 411920040313 is 313040029114.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 409655041849 + 2264998464 = 640043^2 + 47592^2 .
It is a cyclic number.
It is not a de Polignac number, because 411920040313 - 25 = 411920040281 is a prime.
It is a super-2 number, since 2×4119200403132 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (411920040113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205960020156 + 205960020157.
It is an arithmetic number, because the mean of its divisors is an integer number (205960020157).
Almost surely, 2411920040313 is an apocalyptic number.
It is an amenable number.
411920040313 is a deficient number, since it is larger than the sum of its proper divisors (1).
411920040313 is an equidigital number, since it uses as much as digits as its factorization.
411920040313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 28.
Adding to 411920040313 its reverse (313040029114), we get a palindrome (724960069427).
The spelling of 411920040313 in words is "four hundred eleven billion, nine hundred twenty million, forty thousand, three hundred thirteen".
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