Base | Representation |
---|---|
bin | 111011111101000011110… |
… | …000100000000000001011 |
3 | 112120212110121110220220221 |
4 | 323331003300200000023 |
5 | 1020000240132034311 |
6 | 12432412345530511 |
7 | 603442461533134 |
oct | 73750360400013 |
9 | 15525417426827 |
10 | 4120010424331 |
11 | 134931752673a |
12 | 56659b1a3a37 |
13 | 23b6911c2839 |
14 | 1035a3bdac8b |
15 | 72286d1e671 |
hex | 3bf43c2000b |
4120010424331 has 2 divisors, whose sum is σ = 4120010424332. Its totient is φ = 4120010424330.
The previous prime is 4120010424311. The next prime is 4120010424337. The reversal of 4120010424331 is 1334240100214.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4120010424331 is a prime.
It is a super-2 number, since 2×41200104243312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4120010424296 and 4120010424305.
It is not a weakly prime, because it can be changed into another prime (4120010424337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2060005212165 + 2060005212166.
It is an arithmetic number, because the mean of its divisors is an integer number (2060005212166).
Almost surely, 24120010424331 is an apocalyptic number.
4120010424331 is a deficient number, since it is larger than the sum of its proper divisors (1).
4120010424331 is an equidigital number, since it uses as much as digits as its factorization.
4120010424331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 4120010424331 its reverse (1334240100214), we get a palindrome (5454250524545).
The spelling of 4120010424331 in words is "four trillion, one hundred twenty billion, ten million, four hundred twenty-four thousand, three hundred thirty-one".
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