Base | Representation |
---|---|
bin | 111011111101001010100… |
… | …011110100100100111001 |
3 | 112120212202120012122220011 |
4 | 323331022203310210321 |
5 | 1020001003340304431 |
6 | 12432431543501521 |
7 | 603445345522402 |
oct | 73751243644471 |
9 | 15525676178804 |
10 | 4120124541241 |
11 | 134937598a435 |
12 | 5666114578a1 |
13 | 23b6aba39a37 |
14 | 1035b50249a9 |
15 | 72291d61cb1 |
hex | 3bf4a8f4939 |
4120124541241 has 2 divisors, whose sum is σ = 4120124541242. Its totient is φ = 4120124541240.
The previous prime is 4120124541233. The next prime is 4120124541259. The reversal of 4120124541241 is 1421454210214.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4116723318841 + 3401222400 = 2028971^2 + 58320^2 .
It is a cyclic number.
It is not a de Polignac number, because 4120124541241 - 23 = 4120124541233 is a prime.
It is not a weakly prime, because it can be changed into another prime (4120124544241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2060062270620 + 2060062270621.
It is an arithmetic number, because the mean of its divisors is an integer number (2060062270621).
Almost surely, 24120124541241 is an apocalyptic number.
It is an amenable number.
4120124541241 is a deficient number, since it is larger than the sum of its proper divisors (1).
4120124541241 is an equidigital number, since it uses as much as digits as its factorization.
4120124541241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10240, while the sum is 31.
Adding to 4120124541241 its reverse (1421454210214), we get a palindrome (5541578751455).
The spelling of 4120124541241 in words is "four trillion, one hundred twenty billion, one hundred twenty-four million, five hundred forty-one thousand, two hundred forty-one".
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