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4120124541241 is a prime number
BaseRepresentation
bin111011111101001010100…
…011110100100100111001
3112120212202120012122220011
4323331022203310210321
51020001003340304431
612432431543501521
7603445345522402
oct73751243644471
915525676178804
104120124541241
11134937598a435
125666114578a1
1323b6aba39a37
141035b50249a9
1572291d61cb1
hex3bf4a8f4939

4120124541241 has 2 divisors, whose sum is σ = 4120124541242. Its totient is φ = 4120124541240.

The previous prime is 4120124541233. The next prime is 4120124541259. The reversal of 4120124541241 is 1421454210214.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4116723318841 + 3401222400 = 2028971^2 + 58320^2 .

It is a cyclic number.

It is not a de Polignac number, because 4120124541241 - 23 = 4120124541233 is a prime.

It is not a weakly prime, because it can be changed into another prime (4120124544241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2060062270620 + 2060062270621.

It is an arithmetic number, because the mean of its divisors is an integer number (2060062270621).

Almost surely, 24120124541241 is an apocalyptic number.

It is an amenable number.

4120124541241 is a deficient number, since it is larger than the sum of its proper divisors (1).

4120124541241 is an equidigital number, since it uses as much as digits as its factorization.

4120124541241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10240, while the sum is 31.

Adding to 4120124541241 its reverse (1421454210214), we get a palindrome (5541578751455).

The spelling of 4120124541241 in words is "four trillion, one hundred twenty billion, one hundred twenty-four million, five hundred forty-one thousand, two hundred forty-one".