412013233314041 has 4 divisors (see below), whose sum is σ = 412034119085952. Its totient is φ = 411992347542132.

The previous prime is 412013233314029. The next prime is 412013233314119. The reversal of 412013233314041 is 140413332310214.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-412013233314041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 412013233313989 and 412013233314007.

It is not an unprimeable number, because it can be changed into a prime (412013233914041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10442856365 + ... + 10442895818.

It is an arithmetic number, because the mean of its divisors is an integer number (103008529771488).

Almost surely, 2^{412013233314041} is an apocalyptic number.

It is an amenable number.

412013233314041 is a deficient number, since it is larger than the sum of its proper divisors (20885771911).

412013233314041 is a wasteful number, since it uses less digits than its factorization.

412013233314041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20885771910.

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 412013233314041 its reverse (140413332310214), we get a palindrome (552426565624255).

The spelling of 412013233314041 in words is "four hundred twelve trillion, thirteen billion, two hundred thirty-three million, three hundred fourteen thousand, forty-one".