Base | Representation |
---|---|
bin | 1011111111011011110… |
… | …10110111101000001001 |
3 | 1110101110221010200212012 |
4 | 11333231322313220021 |
5 | 23222300430304023 |
6 | 513135411425305 |
7 | 41524036116512 |
oct | 5775572675011 |
9 | 1411427120765 |
10 | 412013525513 |
11 | 149808991987 |
12 | 67a265b5235 |
13 | 2cb1152a315 |
14 | 15d27901a09 |
15 | aab643b978 |
hex | 5fedeb7a09 |
412013525513 has 2 divisors, whose sum is σ = 412013525514. Its totient is φ = 412013525512.
The previous prime is 412013525479. The next prime is 412013525591. The reversal of 412013525513 is 315525310214.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 395530303744 + 16483221769 = 628912^2 + 128387^2 .
It is a cyclic number.
It is not a de Polignac number, because 412013525513 - 218 = 412013263369 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 412013525513.
It is not a weakly prime, because it can be changed into another prime (412013525593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206006762756 + 206006762757.
It is an arithmetic number, because the mean of its divisors is an integer number (206006762757).
Almost surely, 2412013525513 is an apocalyptic number.
It is an amenable number.
412013525513 is a deficient number, since it is larger than the sum of its proper divisors (1).
412013525513 is an equidigital number, since it uses as much as digits as its factorization.
412013525513 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 412013525513 its reverse (315525310214), we get a palindrome (727538835727).
The spelling of 412013525513 in words is "four hundred twelve billion, thirteen million, five hundred twenty-five thousand, five hundred thirteen".
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