Base | Representation |
---|---|
bin | 101110110101110110101101… |
… | …0111011111110101000010010 |
3 | 2000000211220212220222010012122 |
4 | 1131223231122323332220102 |
5 | 413001032111014020132 |
6 | 4020144150432054242 |
7 | 152533416040203401 |
oct | 13553553273765022 |
9 | 2000756786863178 |
10 | 412022033345042 |
11 | 10a31262148176a |
12 | 3a264769394382 |
13 | 148b9684965cc3 |
14 | 73a5d895a7638 |
15 | 329798a567912 |
hex | 176bb5aefea12 |
412022033345042 has 4 divisors (see below), whose sum is σ = 618033050017566. Its totient is φ = 206011016672520.
The previous prime is 412022033344991. The next prime is 412022033345051. The reversal of 412022033345042 is 240543330220214.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 294165410865001 + 117856622480041 = 17151251^2 + 10856179^2 .
It is a junction number, because it is equal to n+sod(n) for n = 412022033344993 and 412022033345011.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 103005508336259 + ... + 103005508336262.
Almost surely, 2412022033345042 is an apocalyptic number.
412022033345042 is a deficient number, since it is larger than the sum of its proper divisors (206011016672524).
412022033345042 is a wasteful number, since it uses less digits than its factorization.
412022033345042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 206011016672523.
The product of its (nonzero) digits is 138240, while the sum is 35.
Adding to 412022033345042 its reverse (240543330220214), we get a palindrome (652565363565256).
The spelling of 412022033345042 in words is "four hundred twelve trillion, twenty-two billion, thirty-three million, three hundred forty-five thousand, forty-two".
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