412022443404353 has 4 divisors (see below), whose sum is σ = 412625697348528. Its totient is φ = 411419189460180.

The previous prime is 412022443404349. The next prime is 412022443404389. The reversal of 412022443404353 is 353404344220214.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 412022443404353 - 2² = 412022443404349 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 412022443404353.

It is not an unprimeable number, because it can be changed into a prime (412022443404053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 301626971063 + ... + 301626972428.

It is an arithmetic number, because the mean of its divisors is an integer number (103156424337132).

Almost surely, 2^{412022443404353} is an apocalyptic number.

It is an amenable number.

412022443404353 is a deficient number, since it is larger than the sum of its proper divisors (603253944175).

412022443404353 is an equidigital number, since it uses as much as digits as its factorization.

412022443404353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 603253944174.

The product of its (nonzero) digits is 1105920, while the sum is 41.

Adding to 412022443404353 its reverse (353404344220214), we get a palindrome (765426787624567).

The spelling of 412022443404353 in words is "four hundred twelve trillion, twenty-two billion, four hundred forty-three million, four hundred four thousand, three hundred fifty-three".