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412035678193 is a prime number
BaseRepresentation
bin1011111111011110011…
…11010111111111110001
31110101112110211011121211
411333233033113333301
523222322113200233
6513141522320121
741524425322546
oct5775717277761
91411473734554
10412035678193
1114981a442587
1267a31ab9041
132cb15cb5509
1415d2a82abcd
15aab83655cd
hex5fef3d7ff1

412035678193 has 2 divisors, whose sum is σ = 412035678194. Its totient is φ = 412035678192.

The previous prime is 412035678121. The next prime is 412035678211. The reversal of 412035678193 is 391876530214.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 315953037409 + 96082640784 = 562097^2 + 309972^2 .

It is a cyclic number.

It is not a de Polignac number, because 412035678193 - 225 = 412002123761 is a prime.

It is not a weakly prime, because it can be changed into another prime (412035678113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206017839096 + 206017839097.

It is an arithmetic number, because the mean of its divisors is an integer number (206017839097).

It is a 1-persistent number, because it is pandigital, but 2⋅412035678193 = 824071356386 is not.

Almost surely, 2412035678193 is an apocalyptic number.

It is an amenable number.

412035678193 is a deficient number, since it is larger than the sum of its proper divisors (1).

412035678193 is an equidigital number, since it uses as much as digits as its factorization.

412035678193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1088640, while the sum is 49.

The spelling of 412035678193 in words is "four hundred twelve billion, thirty-five million, six hundred seventy-eight thousand, one hundred ninety-three".