Base | Representation |
---|---|
bin | 10010101111011000000010… |
… | …01100010110111101100001 |
3 | 12101220122210212111001112021 |
4 | 21113230001030112331201 |
5 | 20400142023143101423 |
6 | 223351415135301441 |
7 | 11452224642514462 |
oct | 1127540114267541 |
9 | 171818725431467 |
10 | 41210231222113 |
11 | 121491851a3828 |
12 | 475699b07a881 |
13 | 19cc153739245 |
14 | a2682b754d69 |
15 | 4b6e8cc3a95d |
hex | 257b01316f61 |
41210231222113 has 2 divisors, whose sum is σ = 41210231222114. Its totient is φ = 41210231222112.
The previous prime is 41210231222099. The next prime is 41210231222119. The reversal of 41210231222113 is 31122213201214.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 24298668879424 + 16911562342689 = 4929368^2 + 4112367^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41210231222113 is a prime.
It is not a weakly prime, because it can be changed into another prime (41210231222119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20605115611056 + 20605115611057.
It is an arithmetic number, because the mean of its divisors is an integer number (20605115611057).
Almost surely, 241210231222113 is an apocalyptic number.
It is an amenable number.
41210231222113 is a deficient number, since it is larger than the sum of its proper divisors (1).
41210231222113 is an equidigital number, since it uses as much as digits as its factorization.
41210231222113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 41210231222113 its reverse (31122213201214), we get a palindrome (72332444423327).
The spelling of 41210231222113 in words is "forty-one trillion, two hundred ten billion, two hundred thirty-one million, two hundred twenty-two thousand, one hundred thirteen".
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