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41210231222113 is a prime number
BaseRepresentation
bin10010101111011000000010…
…01100010110111101100001
312101220122210212111001112021
421113230001030112331201
520400142023143101423
6223351415135301441
711452224642514462
oct1127540114267541
9171818725431467
1041210231222113
11121491851a3828
12475699b07a881
1319cc153739245
14a2682b754d69
154b6e8cc3a95d
hex257b01316f61

41210231222113 has 2 divisors, whose sum is σ = 41210231222114. Its totient is φ = 41210231222112.

The previous prime is 41210231222099. The next prime is 41210231222119. The reversal of 41210231222113 is 31122213201214.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 24298668879424 + 16911562342689 = 4929368^2 + 4112367^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41210231222113 is a prime.

It is not a weakly prime, because it can be changed into another prime (41210231222119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20605115611056 + 20605115611057.

It is an arithmetic number, because the mean of its divisors is an integer number (20605115611057).

Almost surely, 241210231222113 is an apocalyptic number.

It is an amenable number.

41210231222113 is a deficient number, since it is larger than the sum of its proper divisors (1).

41210231222113 is an equidigital number, since it uses as much as digits as its factorization.

41210231222113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 41210231222113 its reverse (31122213201214), we get a palindrome (72332444423327).

The spelling of 41210231222113 in words is "forty-one trillion, two hundred ten billion, two hundred thirty-one million, two hundred twenty-two thousand, one hundred thirteen".