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412122121221233 is a prime number
BaseRepresentation
bin101110110110100101010100…
…0101000111011010001110001
32000001012111020012222000221002
41131231022220220323101301
5413004202101013034413
64020302142214411345
7152543561232130613
oct13555125050732161
92001174205860832
10412122121221233
1110a351012478515
123a280040660b55
13148c5c45732a97
1473aab62180db3
15329a39735e958
hex176d2a8a3b471

412122121221233 has 2 divisors, whose sum is σ = 412122121221234. Its totient is φ = 412122121221232.

The previous prime is 412122121221163. The next prime is 412122121221263. The reversal of 412122121221233 is 332122121221214.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 362738993221264 + 49383127999969 = 19045708^2 + 7027313^2 .

It is a cyclic number.

It is not a de Polignac number, because 412122121221233 - 210 = 412122121220209 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 412122121221196 and 412122121221205.

It is not a weakly prime, because it can be changed into another prime (412122121221263) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206061060610616 + 206061060610617.

It is an arithmetic number, because the mean of its divisors is an integer number (206061060610617).

Almost surely, 2412122121221233 is an apocalyptic number.

It is an amenable number.

412122121221233 is a deficient number, since it is larger than the sum of its proper divisors (1).

412122121221233 is an equidigital number, since it uses as much as digits as its factorization.

412122121221233 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4608, while the sum is 29.

Adding to 412122121221233 its reverse (332122121221214), we get a palindrome (744244242442447).

The spelling of 412122121221233 in words is "four hundred twelve trillion, one hundred twenty-two billion, one hundred twenty-one million, two hundred twenty-one thousand, two hundred thirty-three".