Base | Representation |
---|---|
bin | 10010101111011100001000… |
… | …11100101010011010110011 |
3 | 12101220212111100002210011011 |
4 | 21113232010130222122303 |
5 | 20400211030411431121 |
6 | 223352421441531351 |
7 | 11452333342125055 |
oct | 1127560434523263 |
9 | 171825440083134 |
10 | 41212433311411 |
11 | 1214a10522003a |
12 | 47572b4643b57 |
13 | 19cc414a1c86b |
14 | a26999db78d5 |
15 | 4b706b21b7e1 |
hex | 257b8472a6b3 |
41212433311411 has 2 divisors, whose sum is σ = 41212433311412. Its totient is φ = 41212433311410.
The previous prime is 41212433311297. The next prime is 41212433311429. The reversal of 41212433311411 is 11411333421214.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41212433311411 - 213 = 41212433303219 is a prime.
It is not a weakly prime, because it can be changed into another prime (41212433311211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20606216655705 + 20606216655706.
It is an arithmetic number, because the mean of its divisors is an integer number (20606216655706).
Almost surely, 241212433311411 is an apocalyptic number.
41212433311411 is a deficient number, since it is larger than the sum of its proper divisors (1).
41212433311411 is an equidigital number, since it uses as much as digits as its factorization.
41212433311411 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6912, while the sum is 31.
Adding to 41212433311411 its reverse (11411333421214), we get a palindrome (52623766732625).
The spelling of 41212433311411 in words is "forty-one trillion, two hundred twelve billion, four hundred thirty-three million, three hundred eleven thousand, four hundred eleven".
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