412132222411433 has 4 divisors (see below), whose sum is σ = 412163119210320. Its totient is φ = 412101325612548.

The previous prime is 412132222411421. The next prime is 412132222411519. The reversal of 412132222411433 is 334114222231214.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 412132222411433 - 2¹⁸ = 412132222149289 is a prime.

It is a super-2 number, since 2×412132222411433² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 412132222411393 and 412132222411402.

It is not an unprimeable number, because it can be changed into a prime (412132222411633) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15448379435 + ... + 15448406112.

It is an arithmetic number, because the mean of its divisors is an integer number (103040779802580).

Almost surely, 2^{412132222411433} is an apocalyptic number.

It is an amenable number.

412132222411433 is a deficient number, since it is larger than the sum of its proper divisors (30896798887).

412132222411433 is a wasteful number, since it uses less digits than its factorization.

412132222411433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30896798886.

The product of its digits is 55296, while the sum is 35.

Adding to 412132222411433 its reverse (334114222231214), we get a palindrome (746246444642647).

The spelling of 412132222411433 in words is "four hundred twelve trillion, one hundred thirty-two billion, two hundred twenty-two million, four hundred eleven thousand, four hundred thirty-three".