Base | Representation |
---|---|
bin | 111011111111000000010… |
… | …011001000000001111011 |
3 | 112121001212020011001201102 |
4 | 323333000103020001323 |
5 | 1020014030032012323 |
6 | 12433355550042015 |
7 | 603545322554636 |
oct | 73770023100173 |
9 | 15531766131642 |
10 | 4122099875963 |
11 | 134a199a0a673 |
12 | 566a82aa930b |
13 | 23b935059354 |
14 | 1037214dcc1d |
15 | 7235a4a1328 |
hex | 3bfc04c807b |
4122099875963 has 2 divisors, whose sum is σ = 4122099875964. Its totient is φ = 4122099875962.
The previous prime is 4122099875939. The next prime is 4122099876079. The reversal of 4122099875963 is 3695789902214.
4122099875963 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4122099875963 - 222 = 4122095681659 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4122099875963.
It is not a weakly prime, because it can be changed into another prime (4122099875903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2061049937981 + 2061049937982.
It is an arithmetic number, because the mean of its divisors is an integer number (2061049937982).
It is a 1-persistent number, because it is pandigital, but 2⋅4122099875963 = 8244199751926 is not.
Almost surely, 24122099875963 is an apocalyptic number.
4122099875963 is a deficient number, since it is larger than the sum of its proper divisors (1).
4122099875963 is an equidigital number, since it uses as much as digits as its factorization.
4122099875963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 58786560, while the sum is 65.
The spelling of 4122099875963 in words is "four trillion, one hundred twenty-two billion, ninety-nine million, eight hundred seventy-five thousand, nine hundred sixty-three".
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