Search a number
-
+
4122505402033 is a prime number
BaseRepresentation
bin111011111111011000011…
…110000101011010110001
3112121002220111012220220111
4323333120132011122301
51020020342340331113
612433504113541321
7603561345513454
oct73773036053261
915532814186814
104122505402033
11134a38790a387
12566b76874841
1323b99b083cc5
1410375d30149b
1572380da713d
hex3bfd87856b1

4122505402033 has 2 divisors, whose sum is σ = 4122505402034. Its totient is φ = 4122505402032.

The previous prime is 4122505401979. The next prime is 4122505402049. The reversal of 4122505402033 is 3302045052214.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3856695039409 + 265810362624 = 1963847^2 + 515568^2 .

It is a cyclic number.

It is not a de Polignac number, because 4122505402033 - 213 = 4122505393841 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4122505401986 and 4122505402004.

It is not a weakly prime, because it can be changed into another prime (4122505402063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2061252701016 + 2061252701017.

It is an arithmetic number, because the mean of its divisors is an integer number (2061252701017).

Almost surely, 24122505402033 is an apocalyptic number.

It is an amenable number.

4122505402033 is a deficient number, since it is larger than the sum of its proper divisors (1).

4122505402033 is an equidigital number, since it uses as much as digits as its factorization.

4122505402033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 31.

The spelling of 4122505402033 in words is "four trillion, one hundred twenty-two billion, five hundred five million, four hundred two thousand, thirty-three".