Base | Representation |
---|---|
bin | 101110111000000110010100… |
… | …0111011111010101000001001 |
3 | 2000001221101220202122202212122 |
4 | 1131300030220323322220021 |
5 | 413021110211110110121 |
6 | 4020541552512021025 |
7 | 152564614330400342 |
oct | 13560145073725011 |
9 | 2001841822582778 |
10 | 412330432113161 |
11 | 10a42139954a841 |
12 | 3a2b4497531775 |
13 | 1490c792807693 |
14 | 73b6c83d370c9 |
15 | 32a09da2405ab |
hex | 1770328efaa09 |
412330432113161 has 2 divisors, whose sum is σ = 412330432113162. Its totient is φ = 412330432113160.
The previous prime is 412330432113113. The next prime is 412330432113269. The reversal of 412330432113161 is 161311234033214.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 230672762047225 + 181657670065936 = 15187915^2 + 13478044^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-412330432113161 is a prime.
It is not a weakly prime, because it can be changed into another prime (412330432113661) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206165216056580 + 206165216056581.
It is an arithmetic number, because the mean of its divisors is an integer number (206165216056581).
Almost surely, 2412330432113161 is an apocalyptic number.
It is an amenable number.
412330432113161 is a deficient number, since it is larger than the sum of its proper divisors (1).
412330432113161 is an equidigital number, since it uses as much as digits as its factorization.
412330432113161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 35.
Adding to 412330432113161 its reverse (161311234033214), we get a palindrome (573641666146375).
The spelling of 412330432113161 in words is "four hundred twelve trillion, three hundred thirty billion, four hundred thirty-two million, one hundred thirteen thousand, one hundred sixty-one".
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