Base | Representation |
---|---|
bin | 1100000000000011010… |
… | …11010111011111010001 |
3 | 1110102100000212122122111 |
4 | 12000001223113133101 |
5 | 23223440310143113 |
6 | 513232332305321 |
7 | 41535202502152 |
oct | 6000153273721 |
9 | 1412300778574 |
10 | 412345006033 |
11 | 149969008124 |
12 | 67ab9612241 |
13 | 2cb650cac3c |
14 | 15d5994b929 |
15 | aad55b813d |
hex | 6001ad77d1 |
412345006033 has 2 divisors, whose sum is σ = 412345006034. Its totient is φ = 412345006032.
The previous prime is 412345005991. The next prime is 412345006093. The reversal of 412345006033 is 330600543214.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 410557999504 + 1787006529 = 640748^2 + 42273^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-412345006033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 412345005986 and 412345006004.
It is not a weakly prime, because it can be changed into another prime (412345006093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206172503016 + 206172503017.
It is an arithmetic number, because the mean of its divisors is an integer number (206172503017).
Almost surely, 2412345006033 is an apocalyptic number.
It is an amenable number.
412345006033 is a deficient number, since it is larger than the sum of its proper divisors (1).
412345006033 is an equidigital number, since it uses as much as digits as its factorization.
412345006033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 412345006033 its reverse (330600543214), we get a palindrome (742945549247).
The spelling of 412345006033 in words is "four hundred twelve billion, three hundred forty-five million, six thousand, thirty-three".
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