Base | Representation |
---|---|
bin | 111100000001000100111… |
… | …000010010110110011001 |
3 | 112121021121020122001022002 |
4 | 330001010320102312121 |
5 | 1020033103444241441 |
6 | 12434404405210345 |
7 | 603654412243001 |
oct | 74010470226631 |
9 | 15537536561262 |
10 | 4124324212121 |
11 | 1350130551313 |
12 | 5673a3a009b5 |
13 | 23bbcab2b9a9 |
14 | 103892ab3001 |
15 | 7243a8c8b9b |
hex | 3c044e12d99 |
4124324212121 has 2 divisors, whose sum is σ = 4124324212122. Its totient is φ = 4124324212120.
The previous prime is 4124324212109. The next prime is 4124324212139. The reversal of 4124324212121 is 1212124234214.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3804040656025 + 320283556096 = 1950395^2 + 565936^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4124324212121 is a prime.
It is not a weakly prime, because it can be changed into another prime (4124324212171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062162106060 + 2062162106061.
It is an arithmetic number, because the mean of its divisors is an integer number (2062162106061).
Almost surely, 24124324212121 is an apocalyptic number.
It is an amenable number.
4124324212121 is a deficient number, since it is larger than the sum of its proper divisors (1).
4124324212121 is an equidigital number, since it uses as much as digits as its factorization.
4124324212121 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6144, while the sum is 29.
Adding to 4124324212121 its reverse (1212124234214), we get a palindrome (5336448446335).
The spelling of 4124324212121 in words is "four trillion, one hundred twenty-four billion, three hundred twenty-four million, two hundred twelve thousand, one hundred twenty-one".
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