Base | Representation |
---|---|
bin | 111100000001000101010… |
… | …111010001110001111001 |
3 | 112121021121210220200200212 |
4 | 330001011113101301321 |
5 | 1020033113034143301 |
6 | 12434405255240505 |
7 | 603654541261352 |
oct | 74010527216171 |
9 | 15537553820625 |
10 | 4124332334201 |
11 | 1350135099582 |
12 | 5673a6679135 |
13 | 23bbcc713861 |
14 | 103893bc8d29 |
15 | 7243b4804bb |
hex | 3c0455d1c79 |
4124332334201 has 2 divisors, whose sum is σ = 4124332334202. Its totient is φ = 4124332334200.
The previous prime is 4124332334189. The next prime is 4124332334231. The reversal of 4124332334201 is 1024332334214.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2344512192400 + 1779820141801 = 1531180^2 + 1334099^2 .
It is a cyclic number.
It is not a de Polignac number, because 4124332334201 - 218 = 4124332072057 is a prime.
It is not a weakly prime, because it can be changed into another prime (4124332334231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062166167100 + 2062166167101.
It is an arithmetic number, because the mean of its divisors is an integer number (2062166167101).
Almost surely, 24124332334201 is an apocalyptic number.
It is an amenable number.
4124332334201 is a deficient number, since it is larger than the sum of its proper divisors (1).
4124332334201 is an equidigital number, since it uses as much as digits as its factorization.
4124332334201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 4124332334201 its reverse (1024332334214), we get a palindrome (5148664668415).
The spelling of 4124332334201 in words is "four trillion, one hundred twenty-four billion, three hundred thirty-two million, three hundred thirty-four thousand, two hundred one".
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