Base | Representation |
---|---|
bin | 100110011010010101… |
… | …111010001001100011 |
3 | 10221110101010101220121 |
4 | 212122111322021203 |
5 | 1133431444441011 |
6 | 30540341021111 |
7 | 2660032256335 |
oct | 463225721143 |
9 | 127411111817 |
10 | 41244140131 |
11 | 16545272a27 |
12 | 7bb06b4797 |
13 | 3b73a5cb5c |
14 | 1dd390b455 |
15 | 1115d40e71 |
hex | 99a57a263 |
41244140131 has 2 divisors, whose sum is σ = 41244140132. Its totient is φ = 41244140130.
The previous prime is 41244140099. The next prime is 41244140177. The reversal of 41244140131 is 13104144214.
41244140131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41244140131 - 25 = 41244140099 is a prime.
It is a super-2 number, since 2×412441401312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 41244140096 and 41244140105.
It is not a weakly prime, because it can be changed into another prime (41244140831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20622070065 + 20622070066.
It is an arithmetic number, because the mean of its divisors is an integer number (20622070066).
Almost surely, 241244140131 is an apocalyptic number.
41244140131 is a deficient number, since it is larger than the sum of its proper divisors (1).
41244140131 is an equidigital number, since it uses as much as digits as its factorization.
41244140131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 41244140131 its reverse (13104144214), we get a palindrome (54348284345).
The spelling of 41244140131 in words is "forty-one billion, two hundred forty-four million, one hundred forty thousand, one hundred thirty-one".
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