Base | Representation |
---|---|
bin | 101110111000111010011110… |
… | …0000100010011110110110011 |
3 | 2000002100002222112211011221111 |
4 | 1131301310330010103312303 |
5 | 413024424040042333301 |
6 | 4021105233312534151 |
7 | 152605660465602124 |
oct | 13561647404236663 |
9 | 2002302875734844 |
10 | 412442422230451 |
11 | 10a464937aa7488 |
12 | 3a312130851357 |
13 | 1491a1cc3cb582 |
14 | 73bc46956204b |
15 | 32a3891de7551 |
hex | 1771d3c113db3 |
412442422230451 has 2 divisors, whose sum is σ = 412442422230452. Its totient is φ = 412442422230450.
The previous prime is 412442422230439. The next prime is 412442422230479. The reversal of 412442422230451 is 154032224244214.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-412442422230451 is a prime.
It is not a weakly prime, because it can be changed into another prime (412442422230481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206221211115225 + 206221211115226.
It is an arithmetic number, because the mean of its divisors is an integer number (206221211115226).
Almost surely, 2412442422230451 is an apocalyptic number.
412442422230451 is a deficient number, since it is larger than the sum of its proper divisors (1).
412442422230451 is an equidigital number, since it uses as much as digits as its factorization.
412442422230451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 491520, while the sum is 40.
Adding to 412442422230451 its reverse (154032224244214), we get a palindrome (566474646474665).
The spelling of 412442422230451 in words is "four hundred twelve trillion, four hundred forty-two billion, four hundred twenty-two million, two hundred thirty thousand, four hundred fifty-one".
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