Base | Representation |
---|---|
bin | 101110111000111010110010… |
… | …1010001000010110001011001 |
3 | 2000002100011202201102222020101 |
4 | 1131301311211101002301121 |
5 | 413024431444014343301 |
6 | 4021105430043455401 |
7 | 152606013560666323 |
oct | 13561654521026131 |
9 | 2002304681388211 |
10 | 412443113434201 |
11 | 10a465162189053 |
12 | 3a3122a4227561 |
13 | 1491a2ac67ac85 |
14 | 73bc4d328a613 |
15 | 32a38d292d701 |
hex | 1771d65442c59 |
412443113434201 has 2 divisors, whose sum is σ = 412443113434202. Its totient is φ = 412443113434200.
The previous prime is 412443113434147. The next prime is 412443113434241. The reversal of 412443113434201 is 102434311344214.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 316815934856976 + 95627178577225 = 17799324^2 + 9778915^2 .
It is a cyclic number.
It is not a de Polignac number, because 412443113434201 - 217 = 412443113303129 is a prime.
It is not a weakly prime, because it can be changed into another prime (412443113434241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206221556717100 + 206221556717101.
It is an arithmetic number, because the mean of its divisors is an integer number (206221556717101).
Almost surely, 2412443113434201 is an apocalyptic number.
It is an amenable number.
412443113434201 is a deficient number, since it is larger than the sum of its proper divisors (1).
412443113434201 is an equidigital number, since it uses as much as digits as its factorization.
412443113434201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 110592, while the sum is 37.
Adding to 412443113434201 its reverse (102434311344214), we get a palindrome (514877424778415).
The spelling of 412443113434201 in words is "four hundred twelve trillion, four hundred forty-three billion, one hundred thirteen million, four hundred thirty-four thousand, two hundred one".
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