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4124543131 is a prime number
BaseRepresentation
bin1111010111010111…
…1000100010011011
3101122110001111111201
43311311320202123
531421340340011
61521135135031
7204132016042
oct36565704233
911573044451
104124543131
111827219335
12971374477
13509679487
142b1ad3559
15192176cc1
hexf5d7889b

4124543131 has 2 divisors, whose sum is σ = 4124543132. Its totient is φ = 4124543130.

The previous prime is 4124543119. The next prime is 4124543177. The reversal of 4124543131 is 1313454214.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4124543131 - 215 = 4124510363 is a prime.

It is a super-2 number, since 2×41245431312 = 34023712078958566322, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4124543131.

It is not a weakly prime, because it can be changed into another prime (4124546131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062271565 + 2062271566.

It is an arithmetic number, because the mean of its divisors is an integer number (2062271566).

Almost surely, 24124543131 is an apocalyptic number.

4124543131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4124543131 is an equidigital number, since it uses as much as digits as its factorization.

4124543131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5760, while the sum is 28.

The square root of 4124543131 is about 64222.6060744969. The cubic root of 4124543131 is about 1603.7079538017.

Adding to 4124543131 its reverse (1313454214), we get a palindrome (5437997345).

The spelling of 4124543131 in words is "four billion, one hundred twenty-four million, five hundred forty-three thousand, one hundred thirty-one".