Base | Representation |
---|---|
bin | 111100000001101111000… |
… | …101001011000110011001 |
3 | 112121100102120220011001102 |
4 | 330001233011023012121 |
5 | 1020041031222400241 |
6 | 12435002540401145 |
7 | 604011100303631 |
oct | 74015705130631 |
9 | 15540376804042 |
10 | 4125032231321 |
11 | 1350464178651 |
12 | 567560b461b5 |
13 | 23bcb1718171 |
14 | 10391cb376c1 |
15 | 7247cb3239b |
hex | 3c06f14b199 |
4125032231321 has 2 divisors, whose sum is σ = 4125032231322. Its totient is φ = 4125032231320.
The previous prime is 4125032231267. The next prime is 4125032231351. The reversal of 4125032231321 is 1231322305214.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3684342047296 + 440690184025 = 1919464^2 + 663845^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4125032231321 is a prime.
It is not a weakly prime, because it can be changed into another prime (4125032231351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062516115660 + 2062516115661.
It is an arithmetic number, because the mean of its divisors is an integer number (2062516115661).
Almost surely, 24125032231321 is an apocalyptic number.
It is an amenable number.
4125032231321 is a deficient number, since it is larger than the sum of its proper divisors (1).
4125032231321 is an equidigital number, since it uses as much as digits as its factorization.
4125032231321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 4125032231321 its reverse (1231322305214), we get a palindrome (5356354536535).
The spelling of 4125032231321 in words is "four trillion, one hundred twenty-five billion, thirty-two million, two hundred thirty-one thousand, three hundred twenty-one".
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