4125344010113 has 2 divisors, whose sum is σ = 4125344010114. Its totient is φ = 4125344010112.

The previous prime is 4125344010101. The next prime is 4125344010131. The reversal of 4125344010113 is 3110104435214.

Together with next prime (4125344010131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3811932141889 + 313411868224 = 1952417^2 + 559832^2 .

It is a cyclic number.

It is not a de Polignac number, because 4125344010113 - 2⁴ = 4125344010097 is a prime.

It is not a weakly prime, because it can be changed into another prime (4125344010413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2062672005056 + 2062672005057.

It is an arithmetic number, because the mean of its divisors is an integer number (2062672005057).

Almost surely, 2^{4125344010113} is an apocalyptic number.

It is an amenable number.

4125344010113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4125344010113 is an equidigital number, since it uses as much as digits as its factorization.

4125344010113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 4125344010113 its reverse (3110104435214), we get a palindrome (7235448445327).

The spelling of 4125344010113 in words is "four trillion, one hundred twenty-five billion, three hundred forty-four million, ten thousand, one hundred thirteen".