4125411022401 has 6 divisors (see below), whose sum is σ = 5958927032370. Its totient is φ = 2750274014928.

The previous prime is 4125411022373. The next prime is 4125411022441. The reversal of 4125411022401 is 1042201145214.

4125411022401 is a `hidden beast` number, since 4 + 1 + 2 + 5 + 411 + 0 + 2 + 240 + 1 = 666.

It can be written as a sum of positive squares in only one way, i.e., 2218252784400 + 1907158238001 = 1489380^2 + 1380999^2 .

It is not a de Polignac number, because 4125411022401 - 2³¹ = 4123263538753 is a prime.

It is a super-3 number, since 3×4125411022401³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (4125411022441) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 229189501236 + ... + 229189501253.

It is an arithmetic number, because the mean of its divisors is an integer number (993154505395).

Almost surely, 2^{4125411022401} is an apocalyptic number.

It is an amenable number.

4125411022401 is a deficient number, since it is larger than the sum of its proper divisors (1833516009969).

4125411022401 is a wasteful number, since it uses less digits than its factorization.

4125411022401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 458379002495 (or 458379002492 counting only the distinct ones).

The product of its (nonzero) digits is 2560, while the sum is 27.

Adding to 4125411022401 its reverse (1042201145214), we get a palindrome (5167612167615).

The spelling of 4125411022401 in words is "four trillion, one hundred twenty-five billion, four hundred eleven million, twenty-two thousand, four hundred one".