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41255133301537 is a prime number
BaseRepresentation
bin10010110000101011101011…
…00100001100101100100001
312102001221201011200000210221
421120111311210030230201
520401411003111122122
6223424202510523041
711455404443061151
oct1130256544145441
9172057634600727
1041255133301537
1112166227258681
124763630806481
131a0345b2841cc
14a28a8adb4761
154b8219c856c7
hex25857590cb21

41255133301537 has 2 divisors, whose sum is σ = 41255133301538. Its totient is φ = 41255133301536.

The previous prime is 41255133301519. The next prime is 41255133301549. The reversal of 41255133301537 is 73510333155214.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39110127008481 + 2145006293056 = 6253809^2 + 1464584^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41255133301537 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 41255133301493 and 41255133301502.

It is not a weakly prime, because it can be changed into another prime (41255133307537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20627566650768 + 20627566650769.

It is an arithmetic number, because the mean of its divisors is an integer number (20627566650769).

Almost surely, 241255133301537 is an apocalyptic number.

It is an amenable number.

41255133301537 is a deficient number, since it is larger than the sum of its proper divisors (1).

41255133301537 is an equidigital number, since it uses as much as digits as its factorization.

41255133301537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 567000, while the sum is 43.

The spelling of 41255133301537 in words is "forty-one trillion, two hundred fifty-five billion, one hundred thirty-three million, three hundred one thousand, five hundred thirty-seven".