Base | Representation |
---|---|
bin | 10010110000101100001100… |
… | …10001000101100010011001 |
3 | 12102001222102200220210112121 |
4 | 21120112012101011202121 |
5 | 20401412041324113103 |
6 | 223424250400341241 |
7 | 11455414414544332 |
oct | 1130260621054231 |
9 | 172058380823477 |
10 | 41255413504153 |
11 | 1216636043aa92 |
12 | 47636aa614821 |
13 | 1a034a433cb84 |
14 | a28ab62b3289 |
15 | 4b82346836bd |
hex | 258586445899 |
41255413504153 has 2 divisors, whose sum is σ = 41255413504154. Its totient is φ = 41255413504152.
The previous prime is 41255413504147. The next prime is 41255413504181. The reversal of 41255413504153 is 35140531455214.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20888894370969 + 20366519133184 = 4570437^2 + 4512928^2 .
It is a cyclic number.
It is not a de Polignac number, because 41255413504153 - 29 = 41255413503641 is a prime.
It is not a weakly prime, because it can be changed into another prime (41255413004153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20627706752076 + 20627706752077.
It is an arithmetic number, because the mean of its divisors is an integer number (20627706752077).
Almost surely, 241255413504153 is an apocalyptic number.
It is an amenable number.
41255413504153 is a deficient number, since it is larger than the sum of its proper divisors (1).
41255413504153 is an equidigital number, since it uses as much as digits as its factorization.
41255413504153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720000, while the sum is 43.
Adding to 41255413504153 its reverse (35140531455214), we get a palindrome (76395944959367).
The spelling of 41255413504153 in words is "forty-one trillion, two hundred fifty-five billion, four hundred thirteen million, five hundred four thousand, one hundred fifty-three".
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