Base | Representation |
---|---|
bin | 100110011011100011… |
… | …001101101100000011 |
3 | 10221111210020222102121 |
4 | 212123203031230003 |
5 | 1134002141432001 |
6 | 30542343225111 |
7 | 2660366441326 |
oct | 463343155403 |
9 | 127453228377 |
10 | 41264405251 |
11 | 16555754463 |
12 | 7bb7448197 |
13 | 3b78006b54 |
14 | 1dd64a47bd |
15 | 11179e56a1 |
hex | 99b8cdb03 |
41264405251 has 2 divisors, whose sum is σ = 41264405252. Its totient is φ = 41264405250.
The previous prime is 41264405239. The next prime is 41264405291. The reversal of 41264405251 is 15250446214.
41264405251 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41264405251 - 217 = 41264274179 is a prime.
It is a super-2 number, since 2×412644052512 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (41264405291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20632202625 + 20632202626.
It is an arithmetic number, because the mean of its divisors is an integer number (20632202626).
Almost surely, 241264405251 is an apocalyptic number.
41264405251 is a deficient number, since it is larger than the sum of its proper divisors (1).
41264405251 is an equidigital number, since it uses as much as digits as its factorization.
41264405251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38400, while the sum is 34.
The spelling of 41264405251 in words is "forty-one billion, two hundred sixty-four million, four hundred five thousand, two hundred fifty-one".
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