Base | Representation |
---|---|
bin | 101110111100110011011101… |
… | …0001101000111100000100001 |
3 | 2000011020020010011111101002021 |
4 | 1131321212322031013200201 |
5 | 413112204112242204324 |
6 | 4022155022310021441 |
7 | 152662416611266222 |
oct | 13571467215074041 |
9 | 2004206104441067 |
10 | 412977114413089 |
11 | 10a6506798821a6 |
12 | 3a399894047881 |
13 | 14958761a65c65 |
14 | 73da2b0045249 |
15 | 32b2738555ae4 |
hex | 17799ba347821 |
412977114413089 has 2 divisors, whose sum is σ = 412977114413090. Its totient is φ = 412977114413088.
The previous prime is 412977114413063. The next prime is 412977114413141. The reversal of 412977114413089 is 980314411779214.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 412877000390625 + 100114022464 = 20319375^2 + 316408^2 .
It is a cyclic number.
It is not a de Polignac number, because 412977114413089 - 25 = 412977114413057 is a prime.
It is not a weakly prime, because it can be changed into another prime (412977114413389) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206488557206544 + 206488557206545.
It is an arithmetic number, because the mean of its divisors is an integer number (206488557206545).
Almost surely, 2412977114413089 is an apocalyptic number.
It is an amenable number.
412977114413089 is a deficient number, since it is larger than the sum of its proper divisors (1).
412977114413089 is an equidigital number, since it uses as much as digits as its factorization.
412977114413089 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12192768, while the sum is 61.
The spelling of 412977114413089 in words is "four hundred twelve trillion, nine hundred seventy-seven billion, one hundred fourteen million, four hundred thirteen thousand, eighty-nine".
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