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413004013003 = 5912899542683
BaseRepresentation
bin1100000001010001111…
…01010001110111001011
31110111000221220200021001
412000220331101313023
523231313011404003
6513421553155431
741560424121241
oct6005075216713
91414027820231
10413004013003
1114a176aa888a
126806225bb77
132cc3b7b67aa
1415dbd294791
15ab2338e61d
hex6028f51dcb

413004013003 has 8 divisors (see below), whose sum is σ = 420037416000. Its totient is φ = 405971721288.

The previous prime is 413004012961. The next prime is 413004013043. The reversal of 413004013003 is 300310400314.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-413004013003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (413004013043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 489700 + ... + 1032382.

It is an arithmetic number, because the mean of its divisors is an integer number (52504677000).

Almost surely, 2413004013003 is an apocalyptic number.

413004013003 is a deficient number, since it is larger than the sum of its proper divisors (7033402997).

413004013003 is a wasteful number, since it uses less digits than its factorization.

413004013003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 555641.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 413004013003 its reverse (300310400314), we get a palindrome (713314413317).

The spelling of 413004013003 in words is "four hundred thirteen billion, four million, thirteen thousand, three".

Divisors: 1 59 12899 542683 761041 32018297 7000068017 413004013003